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A problematic case

Brute force: \exp{(-x)}=\sum_{n=0}^{\infty}(-1)^n\frac{x^n}{n!}

Recursion relation for \exp{(-x)}=\sum_{n=0}^{\infty}s_n=\sum_{n=0}^{\infty}(-1)^n\frac{x^n}{n!} s_n=-s_{n-1}\frac{x}{n}, \exp{(x)}=\sum_{n=0}^{\infty}s_n \exp{(-x)}=\frac{1}{\exp{(x)}}