Brute force: exp(−x)=∞∑n=0(−1)nxnn!
Recursion relation for exp(−x)=∞∑n=0sn=∞∑n=0(−1)nxnn! sn=−sn−1xn, exp(x)=∞∑n=0sn exp(−x)=1exp(x)