Processing math: 100%

 

 

 

Error Analysis

ϵ=log10(|fcomputedfexactfexact|), ϵtot=ϵapprox+ϵro.

For the computed second derivative we have f0=fh2f0+fhh22j=1f(2j+2)0(2j+2)!h2j, and the truncation or approximation error goes like ϵapproxf(4)012h2.