New expression for the derivative

With these definitions we obtain the following partial derivatives

$$\frac{\partial a}{\partial x} = 2x,$$

and

$$\frac{\partial b}{\partial a} = \exp{a},$$

and

$$\frac{\partial c}{\partial a} = 1,$$

and

$$\frac{\partial c}{\partial b} = 1,$$

and

$$\frac{\partial d}{\partial c} = \frac{1}{2\sqrt{c}},$$

and finally

$$\frac{\partial f}{\partial d} = 1.$$

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