New expression for the derivative

With these definitions we obtain the following partial derivatives

$$ \frac{\partial a}{\partial x} = 2x, $$

and

$$ \frac{\partial b}{\partial a} = \exp{a}, $$

and

$$ \frac{\partial c}{\partial a} = 1, $$

and

$$ \frac{\partial c}{\partial b} = 1, $$

and

$$ \frac{\partial d}{\partial c} = \frac{1}{2\sqrt{c}}, $$

and finally

$$ \frac{\partial f}{\partial d} = 1. $$