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Gaussian Elimination

The new coefficients are b1k=a(1)1kk=1,,n, where each a(1)1k is equal to the original a1k element. The other coefficients are a(2)jk=a(1)jka(1)j1a(1)1ka(1)11j,k=2,,n, with a new right-hand side given by y1=w(1)1,w(2)j=w(1)ja(1)j1w(1)1a(1)11j=2,,n. We have also set w(1)1=w1, the original vector element. We see that the system of unknowns x1,,xn is transformed into an (n1)×(n1) problem.