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Simple expressions for project 1

For the special matrix we can can actually precalculate the updated matrix elements \tilde{d}_i . The non-diagonal elements e_i are unchanged. For our particular matrix in project 1 we have \tilde{d}_i= 2 - \frac{1}{\tilde{d}_{i-1}}=\frac{i+1}{i}, and the new righthand side \tilde{f}_i given by \tilde{f}_i= f_i + \frac{(i-1)\tilde{f}_{i-1}}{i}. Recall that \tilde{d}_1=2 and \tilde{f}_1=f_1 . These arrays can be set up before computing u .

The backward substitution gives then the final solution u_{i-1}= \frac{i-1}{i}\left(\tilde{f}_{i-1}+u_i\right), with u_n=\tilde{f}_{n}/\tilde{b}_{n} .