Simple expressions for project 1
For the special matrix we can can actually precalculate the updated matrix elements
\tilde{d}_i . The non-diagonal elements
e_i are unchanged.
For our particular matrix in project 1 we have
\tilde{d}_i= 2 - \frac{1}{\tilde{d}_{i-1}}=\frac{i+1}{i},
and the new righthand side
\tilde{f}_i given by
\tilde{f}_i= f_i + \frac{(i-1)\tilde{f}_{i-1}}{i}.
Recall that
\tilde{d}_1=2 and
\tilde{f}_1=f_1 . These arrays can be set up before computing
u .
The backward substitution gives then the final solution
u_{i-1}= \frac{i-1}{i}\left(\tilde{f}_{i-1}+u_i\right),
with u_n=\tilde{f}_{n}/\tilde{b}_{n} .