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Discussion of Jacobi's method for eigenvalues

We have B=(a11a12ca13sa12s+a13ca12ca13sa22c2+a33s22a23sc(a22a33)sc+a23(c2s2)a12s+a13c(a22a33)sc+a23(c2s2)a22s2+a33c2+2a23sc). or b11=a11b12=a12cosθa13sinθ,12,13b13=a13cosθ+a12sinθ,12,13b22=a22cos2θ2a23cosθsinθ+a33sin2θb33=a33cos2θ+2a23cosθsinθ+a22sin2θb23=(a22a33)cosθsinθ+a23(cos2θsin2θ) We will fix the angle θ so that b23=0.