Note that uuT is an outer product giving a matrix of dimension ((n−1)×(n−1)). Each matrix element of P then reads Pij=δij−2uiuj, where i and j range from 1 to n−1. Applying the transformation S1 results in ST1AS1=(a11(Pv)TPvA′), where vT={a21,a31,⋯,an1} and $\mathbf{P}$s must satisfy (Pv)T={k,0,0,⋯}. Then Pv=v−2u(uTv)=ke, with eT={1,0,0,…0}.